Class 8 Maths – Chapter 8

Comparing Quantities

Model Question Paper (Solved)

Section A – Very Short Answer (1 × 5 = 5 Marks)

Q1. Find 10% of 250.

Answer: (10 ÷ 100) × 250 = 25

Q2. If CP = ₹400 and SP = ₹450, find profit.

Answer: Profit = 450 − 400 = ₹50

Q3. Write the formula for Simple Interest.

Answer: SI = (P × R × T) ÷ 100

Q4. What is marked price?

Answer: Marked Price is the price written on the article.

Q5. Define discount.

Answer: Discount = Marked Price − Selling Price

Section B – Short Answer (2 × 5 = 10 Marks)

Q6. Find 25% of 640.

Answer:
25% = 25 ÷ 100
= (25 ÷ 100) × 640 = 160

Q7. CP = ₹800, SP = ₹720. Find loss %.

Answer:
Loss = 800 − 720 = 80
Loss % = (80 ÷ 800) × 100 = 10%

Q8. MP = ₹1200, Discount = ₹240. Find SP.

Answer:
SP = 1200 − 240 = ₹960

Q9. Find SI on ₹1000 at 5% for 2 years.

Answer:
SI = (1000 × 5 × 2) ÷ 100 = ₹100

Q10. What is Amount?

Answer: Amount = Principal + Simple Interest

Section C – Long Answer (4 × 5 = 20 Marks)

Q11. A shopkeeper buys an article for ₹1500 and sells it for ₹1800. Find profit %.

Answer:
CP = 1500, SP = 1800
Profit = 1800 − 1500 = 300
Profit % = (300 ÷ 1500) × 100 = 20%

Q12. Find the amount if ₹2500 is invested at 8% p.a. for 3 years.

Answer:
SI = (2500 × 8 × 3) ÷ 100 = 600
Amount = 2500 + 600 = ₹3100

Q13. An article marked at ₹2000 is sold at a discount of 15%. Find selling price.

Answer:
Discount = 15% of 2000 = 300
SP = 2000 − 300 = ₹1700

Q14. Find the rate of interest if SI is ₹400, P = ₹2000, T = 2 years.

Answer:
400 = (2000 × R × 2) ÷ 100
R = 10%

Q15. Write any two differences between Profit and Discount.

Answer:
1) Profit is gain on CP, Discount is reduction on MP
2) Profit increases SP, Discount decreases SP